McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
1. Graphing Quadratic Functions
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Exercise 66 Page 101

Practice makes perfect
a

We want to find the domain of the given quadratic function.

f(x)=x^2-9 We can find its domain by graphing it. To do so, let's first make a table of values.

x x^2-9 y=x^2-9
-3 ( -3)^2-9 0
-2 ( -2)^2-9 -5
0 0^2-9 -9
2 2^2-9 -5
3 3^2-9 0

Next, we will plot the obtained points on the coordinate plane and connect them with a parabola.

We see above that the x-variable can take any value. With this in mind, we can state the domain. Domain: all real numbers

b

To find the range of the function, we will again interpret its graph.

As we can see, the y-variable only takes values greater than or equal to -9. Range: y≥ - 9

c

Looking at the graph, we can conclude that for x-values between the x-intercepts of the parabola, the value of f(x) is negative.


Let's find the x-intercepts of the graph! To do so, we substitute 0 for f(x) in the function and solve for x.

f(x)=x^2-9
0=x^2-9
9=x^2
±3=x
x=±3

As a result, f(x) is negative for x-values between -3 and 3. -3 < x < 3

d

Since f(x) is a radical function,to find its domain and range, we should interpret the radicand. Recall that the radicand must be non-negative.

f(x)=sqrt(x^2-9) ⇒ x^2-9 ≥ 0 Since the radicand is greater than or equal to 0, then sqrt(x^2-9) is also greater than or equal to 0. With this in mind, we can state the range of the function. Range: y≥ 0 To find its domain, we should determine the x-values for which the radicand is non-negative. Therefore, we will examine the graph of y= x^2-9.

For x-values less than or equal to -3 and greater than or equal to 3, the radicand is non-negative. With this, we can determine the domain as shown below. Domain: x≤ -3 and x ≥ 3