Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
B
b
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
C
c
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
A
a
Minimum
B
b
-56
C
c
Domain: {All real numbers} Range: {y | y ≥ - 56}
Practice makes perfect
a
For a quadratic function y=ax^2+bx+c, the y-coordinate of the vertex is the minimum value of the function when a>0.
Let's identify the values of a, b, and c in the given quadratic function.
y=4x^2+40x+44
⇕
f(x)= 4x^2+ 40x+ 44
We can see above that a= 4, b= 40, and c= 44. We will now use these values to find the desired information. Since a= 4 is greater than 0, the parabola will open upwards. This means it will have a minimum value.
b
The minimum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= 4 and b= 40 in - b2a.
This tells us that the minimum value of the function is - 56.
c
Unless there are any specified restrictions on the x-values, the domain of a quadratic function is all real numbers. Therefore, the domain of this function is all real numbers. Furthermore, since a= 4 is greater than 0, the range is all values greater than or equal to the minimum value, - 56.
Domain:& {All real numbers}
Range:& {y | y ≥ - 56}
