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Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Maximum
33
Domain: {All real numbers}
Range: {y | y ≤ 33}
For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.
Let's identify the values of a, b, and c in the given quadratic function. y=- x^2-14x-16 ⇕ y= - 1x^2+( - 14)x+( - 16) We can see above that a= - 1, b= - 14, and c= - 16. We will now use these values to find the desired information. Since a= - 1 is less than 0, the parabola will open downwards. This means it will have a maximum value.
The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 1 and b= - 14 in - b2a.
a= - 1, b= - 14
Multiplication Property of -1
- a/- b=a/b
Calculate quotient
Now we have to substitute - 7 for x in the given equation.
x= - 7
Calculate power
- a(- b)=a* b
Distribute -1
Add and subtract terms
This tells us that the maximum value of the function is 33.