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Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Start by identifying a, b, and c. The maximum value of the given quadratic function is f ( - b2a ).
Maximum
50
Domain: {All real numbers}
Range: {y | y ≤ 50}
For the quadratic function h(x)=ax^2+bx+c, the y-coordinate of the vertex is the maximum value of the function when a<0.
Let's identify the values of a, b, and c in the given quadratic function. y=- 2x^2-16x+18 ⇕ y= - 2x^2+( - 16)x+ 18 We can see above that a= - 2, b= - 16, and c= 18. We will now use these values to find the desired information. Since a= - 2 is less than 0, the parabola will open downwards. This means it will have a maximum value.
The maximum value is given by substituting - b2a for x. Before we find the value of the function at this point, we need to substitute a= - 2 and b= - 16 in - b2a.
a= - 2, b= - 16
a(- b)=- a * b
- a/- b=a/b
Calculate quotient
Now we have to substitute - 4 for x in the given equation.
x= - 4
Calculate power
- a(- b)=a* b
(- a)b = - ab
Add and subtract terms
This tells us that the maximum value of the function is 50.