Exercise 44 Page 145

To solve a quadratic equation in the form x^2=n, take the square root of each side. For any number n≥ 0, if x^2=n, then x=±sqrt(n). Keeping this in mind, let's consider the given equation.

x^2+6x+9=16

FacPosPerfectSquare

a^2+2ab+b^2=(a+b)^2

(x+3)^2=16

SqrtEqn

sqrt(LHS)=sqrt(RHS)

sqrt((x+3)^2)=sqrt(16)

CalcRoot

Calculate root

x+3=±4

SubEqn

LHS-3=RHS-3

x=-3±4

Both x=-3-4=-7, and x=-3+4=1 are solutions of the equation.