McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
6. Analyzing Functions with Successive Differences
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Exercise 39 Page 145

To find the area of a rectangle, we multiply its length by its width.

B

Practice makes perfect

To find the value of l, recall that the area of a rectangle is found by multiplying its length by its width. We see in the diagram that the area is A=220ft^2, the length is l +12 ft, and the width is l ft.

Solving for l

We can create an equation to solve for l by substituting the given expressions into the formula for the area of a rectangle. A=l * (l+12) ⇒ 220=l(l+12)Let's simplify the this equation. We will start by distributing the l on the right-hand side.
220=l(l+12)
220=l^2+12l
0=l^2+12l-220
l^2+12l-220=0
Now we can factor the quadratic trinomial on the left-hand side of the equation. Here you can see a step-by-step guide on how to factor quadratic trinomials.
l^2+12l-220=0
l^2-10l+22l-220=0
Factor out l & 22
l(l-10)+22l-220=0
l(l-10)+22(l-10)=0
(l-10)(l+22)=0
Next, we will use the Zero Product Property to solve the equation.
(l-10)(l+22)=0
lcl-10=0 & (I) l+22=0 & (II)
(I), (II): Solve for l
lx=10 l+22=0
ll=10 l=- 22
The solutions of this equation are l=10 and l=- 22.

Finding the Dimensions

We need to determine which of the solutions that we found will satisfy the given conditions of our rectangle. To do this, let's substitute these values into the expressions for the length and the width of the rectangle. Then we can evaluate the reasonableness of each measurement.

Length (l+12) Width (l)
l= 10 10+12=
22
10
l= - 22 - 22 +12=
- 10
- 22

If l=- 22, the length and the width are both negative. This does not make sense, because a rectangle cannot have negative dimensions. Therefore, l=10 and the dimensions of the rectangle are 22ft and 10ft.

Checking Our Solution

We can check this solution by solving and seeing that the area is 220ft^2 when the dimensions are multiplied.
A=l * (l+12)
220? =10* 22
220=220
Therefore we are sure that l=10, and the correct answer is B.