McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
6. Analyzing Functions with Successive Differences
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Exercise 34 Page 144

Let f(x)=mx+b represent a linear function and let f(x)=a^x represent an exponential function.

See solution.

Practice makes perfect

We are asked to write a paragraph proof about linear and exponential functions. First, we will write a proof to show that linear functions grow by equal differences over equal intervals. Next, we will show that exponential functions grow by equal factors over equal intervals. At the end we will create our proof.

Linear

Let f(x)=mx+b represent a linear function for some values of m and b. Let l be the fixed length of an interval. We want to show that the function grows by equal differences over equal intervals.

Given: f(x)=mx+b

Prove: Function f(x) grows by equal differences over equal intervals.

Let x_0 be the starting point of the interval with length l. Then, the endpoint of the interval is x_0+l.

To show that f(x) grows by equal differences, it is enough to show that the difference Δ y — which is the difference between the values at the endpoints of the interval — is constant.

Conjecture: Δ y=f(x_0+l)-f(x_0) is constant.

First, let's find the values of f(x_0) and f(x_0+l).

x mx+b f(x)
x_0 mx_0+b f(x_0)=mx_0+b
x_0+l m(x_0+l)+b =mx_0+ml+b f(x_0+l)=mx_0+ml+b
Now, let's find the difference Δ y.
Δ y = f(x_0+l)- f(x_0)
Δ y = mx_0+ml+b-( mx_0+b)
Simplify right-hand side
Δ y = mx_0+ml+b-mx_0-b
Δ y= ml
The difference Δ y=ml depends only on the constants m and l. This tells us that the function f(x) grows by equal differences over equal intervals, which ends the proof.

Exponential

Let f(x)=a^x represent an exponential function for some value of a, where a>0 and a≠ 1. Let l be the fixed length of an interval. We want to show that the function grows by equal factors over equal intervals.

Given: f(x)=a^x

Prove: Function f(x) grows by equal factors over equal intervals.

Let x_0 be the startpoint of the interval with length l. Then, the endpoint of the interval is x_0+l.

To show that f(x) grows by equal factors, it is enough to show that the ratio between the values at the endpoints of the interval, f(x_0+l)f(x_0), is constant.

Conjecture: f(x_0+l)/f(x_0) is constant.

First, let's find the values of f(x_0) and f(x_0+l).

x a^x f(x)=a^x
x_0 a^()darkorangex_0 f(x_0)=a^(x_0)
x_0+l a^()darkorangex_0+l f(x_0+l)=a^(x_0+l)
Now, let's find the ratio.
Ratio = f(x_0+l)/f(x_0)
Ratio = a^(x_0+l)/a^(x_0)
Simplify right-hand side
Ratio = a^(x_0+l-x_0)
Ratio= a^l
The ratio a^l depends only on the constants a and l. This tells us that the function f(x) grows by equal factors over equal intervals, which ends the proof. To show that f(x) grows by equal factors, it is enough to show that the ratio between the values at the endpoints of the interval, f(x_0+l)f(x_0), is constant.

Paragraph Proof for Linear Functions

Based on the complete proof for linear functions, we will write a paragraph proof.

Paragraph Proof

Let f(x)=mx+b be a linear function for some values of m and b. Let l be the fixed length of an interval with endpoints of x_0 and x_0+l. We will show that Δ y=f(x_0+l)-f(x_0) is constant. Since f(x_0)=mx_0+b and f(x_0+l)= m(x_0+l)+b= mx_0+ml+b, we get that Δ y= mx_0+ml+b-(mx_0+b)= ml. The expression ml does not depend on x_0. Therefore, we end the proof.

Paragraph Proof for Exponential Functions

Finally, we will write a paragraph proof for exponential functions.

Paragraph Proof

Let f(x)=a^x be an exponential function for some value of a, where a>0 and a≠ 1. Let l be the fixed length of an interval with endpoints of x_0 and x_0+l. We will show that the quotient f(x_0+l)/f(x_0) is constant. Since f(x_0)=a^(x_0) and f(x_0+l)= a^(x_0+l), we get that f(x_0+l)/f(x_0)= a^(x_0+l)/a^(x_0)=a^l. The expression a^l does not depend on x_0. This ends the proof.