McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Simulations
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Exercise 29 Page 914

1/120

Practice makes perfect

Paige is choosing between 10 books in a library. We are asked about the probability that she selects 3 particular books. First, we will find the number of possible ways she can select 3 books. Since the order of choosing the books does not matter, we will use combinations.

Combinations

The number of n distinct objects taken r at a time is denoted _nC_r and can be calculated using the following formula. _nC_r=n!/( n- r)! r!

In total, there are 10 books and Paige is choosing 3 of them. Let's substitute n= 10 and r= 3 into the formula.
_nC_r=n!/(n-r)!r!
_(10)C_3=10!/( 10- 3)! 3!
_(10)C_3=10!/7!3!

Write as a product

_(10)C_3=10*9*8*7!/7!*3*3*2*1
_(10)C_3=10*9*8*7!/7!*3*2*1
_(10)C_3=10*9*8/3*2*1
_(10)C_3=720/6
_(10)C_3=120
Paige can select 3 books in 120 different ways. Therefore, the probability that she chooses one specific combination of the books is 1 divided by 120. Probability=1/120