McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
5. Volumes of Pyramids and Cones
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Exercise 50 Page 847

Find the area of a regular hexagon.

About 54.35 square inches

Practice makes perfect

Let's analyze the given shaded region. Divide the regular hexagon into six congruent equilateral triangles.

We are asked to find its area. Notice that it is equal to the difference between the area of the circle and the area of the regular hexagon. c Area of Region = c Area of Circle - c Area of Hexagon The radius of the circle is half of its diameter. Therefore, r= 202=10 inches. Now we can use the formula for the area of a circle.

A_\text{circle}=\pi r^2
A_\text{circle}=\pi ({\color{#009600}{10}})^2
A_\text{circle}=100\pi

The area of the circle is 100Ï€ square inches. We will find the area of the hexagon. The hexagon consists of 6 equilateral triangles. Each side of the triangle is s=10 cm. Let's use the formula the area of an equilateral triangle.

A_\text{hexagon}=6A_\Delta
â–¼
Substitute values and evaluate
A_\text{hexagon}=6\cdot{\color{#0000FF}{\dfrac{s^2\sqrt{3}}{4}}}
A_\text{hexagon}=6\cdot\dfrac{({\color{#009600}{10}})^2\sqrt{3}}{4}
A_\text{hexagon}=6\cdot\dfrac{100\sqrt{3}}{4}
A_\text{hexagon}=6\cdot 25\sqrt{3}
A_\text{hexagon}=150\sqrt{3}

Therefore, the area of the hexagon is 150sqrt(3) square inches. Finally, let's find the area of the shaded region. c Area of Region = c Area of Circle - c Area of Hexagon ⇓ c Area of Region = 100π- 150sqrt(3) This tells us that the area of the shaded region is 100π-150sqrt(3) square inches. Let's approximate the answer.

A_\text{region}=100\pi - 150\sqrt{3}
A_\text{region}=54.351644\ldots
A_\text{region}\approx 54.35

The area of the shaded region is about 54.35 square inches.