McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Volumes of Pyramids and Cones
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Exercise 20 Page 845

Use the formula for the volume of a cone.

3.1ft^3

Practice makes perfect

To calculate the volume of a cone, we can use the following formula. In this formula r is the radius and h is the height of a cone. V= 13π r^2 h We are given that the slant height of the cone is 2ft and an angle between the slant height and radius is 47^(∘). Let's notice that the slant height, radius, and the height form a right triangle.

The trigonometric function which connects height and the slant height is the sine. sin θ =opposite/hypotenuse Let's substitute the values and calculate the height.

sinθ=opposite/hypotenuse
sin 47^(∘)=h/2
â–¼
Solve for h
2sin47^(∘)=h
h=2sin47^(∘)
h=1.4627...
h≈ 1.5

The height of the cone is approximately 1.5 ft. Now let's use a fact that the trigonometric function which connects the radius and the slant height is the cosine. cosθ =adjacent/hypotenuse Let's substitute the values and calculate the radius.

cos(θ )=adjacent/hypotenuse
cos47^(∘)=r/2
â–¼
Solve for r
2cos47^(∘)=r
r=2cos47^(∘)
r=1.36399...
r≈ 1.4

The radius of the cone is approximately 1.4 ft. Now we have all values to calculate the volume.

V=1/3Ï€ r^2 h
V=1/3Ï€ ( 1.4)^2 ( 1.5)
â–¼
Simplify right-hand side
V=1/3Ï€(1.96)(1.5)
V=1/3(1.96)(1.5)Ï€
V=2.94/3Ï€
V=3.0787...
V≈ 3.1

The volume of the cone is approximately 3.1ft^3.