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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

4. Volumes of Prisms and Cylinders

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Exercise 60 Page 838

The area of a kite is half the product of its diagonals.

120in^2

Practice makes perfect

We are given a kite and asked to find its area.

The area of a kite is half the product of its diagonals. We can see from the diagram that one of the diagonals has length d_1 = 12in, while the other is divided into two segments of length 7in. and 13in. By the Segment Addition Postulate, the length of the second diagonal is the sum of the lengths of those segments. d_2 = 7in.+13in. ⇔ d_2 = 20in. Using the diagonal lengths, let's find the area of the kite.

A=1/2d_1 d_2

d_1= 12, d_2= 20

A=1/2( 12)(20)

Multiply

A=120

The area of the kite is 120in^2.

Subchapter links

Exercises p.834-838