McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
4. Volumes of Prisms and Cylinders
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Exercise 25 Page 835

Use the formula for the volume of a cylinder.

35.1 centimeters

Practice makes perfect
A cylindrical can of baked potato chips has a height of 27 centimeters and a radius of 4 centimeters.
A new can is advertised as being 30 % larger than the regular can. Both cans have the same radius.
Let h_\text{new} denote the height of the larger can. We can use the formula for the volume of a cylinder.
Cylider Old New
Radius r= 4 r= 4
Height h= 27 {\color{#009600}{h}}={\color{#009600}{h_\text{new}}}
Volume V=π r^2 h
\textcolor{darkorange}{V_\text{old}}=\pi ({\color{#0000FF}{4}})^2({\color{#009600}{27}})=\textcolor{darkorange}{432\pi} \textcolor{darkviolet}{V_\text{new}}=\pi ({\color{#0000FF}{4}})^2{\color{#009600}{h_\text{new}}}=\textcolor{darkviolet}{16\pi h_\text{new}}
The new can is 30 % larger. This tells us that \textcolor{darkviolet}{V_\text{new}}=130\, \%\cdot\textcolor{darkorange}{V_\text{old}}. Let's use that equation and substitute the known values and expressions to find the value of the height of the new can, h_\text{new}.
\textcolor{darkviolet}{V_\text{new}}=130\, \%\cdot\textcolor{darkorange}{V_\text{old}}
\textcolor{darkviolet}{16\pi h_\text{new}}=130\, \%\cdot \textcolor{darkorange}{432\pi}
Solve for h_\text{new}
16\pi h_\text{new}=\dfrac{130}{100}\cdot 432\pi
16\pi h_\text{new}=1.3\cdot 432\pi
16\pi h_\text{new}=561.6\pi
h_\text{new}=\dfrac{561.6\pi}{16\pi}
h_\text{new}=\dfrac{561.6}{16}
h_\text{new}=35.1
Finally, we get that the height of the new larger can is 35.1 centimeters.