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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

2. Surface Areas of Prisms and Cylinders

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Exercise 48 Page 821

Substitute the value for the variable.

f(-2)=9

Practice makes perfect

To evaluate a function for a certain value of x, we need to substitute the given value for every instance of x. Let's do this for the given function when x=- 2.

f(x)=x^3 + 4x^2 -2x - 3

x= -2

f( -2)=( -2)^3 +4( -2)^2 - 2( -2)-3

NegBaseToNegPow

(- a)^3 = - a^3

f(-2)= -8 +4(-2)^2 - 2(-2)-3

NegBaseToPosPow

(- a)^2 = a^2

f(-2)=-8 +4(4) - 2(-2)-3

Multiply

f(-2)=-8 + 16 - 2(-2)-3

a(- b)=- a * b

f(-2)=-8 + 16 - (-4)-3

a-(- b)=a+b

f(-2)=-8 + 16 +4 -3

Add and subtract terms

f(-2)=9

When x=-2, the value of the function is 9.

Subchapter links

Exercises p.817-821