2. Surface Areas of Prisms and Cylinders
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Notice that the base areas are different. What must happen if you want the cylinders to have bases with different areas?
See solution.
Let's consider two right cylinders C_1 and C_2. Below, we write the surface area of each cylinder.
| Surface area of C_1 | Surface area of C_2 |
|---|---|
| S_1 = π r_1^2 + 2π r_1h_1 | S_2 = π r_2^2 + 2π r_2h_2 |
However, we must consider numbers so that r_1h_1 = r_2h_2. Below, we pick an example combination of numbers that works. r_1 = 3, h_1 = 4 and r_2 = 4, h_2 = 3
r_1= 3, L_(C_1)= 24π
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r_2= 4, L_(C_2)= 24π
Calculate power
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