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Notice that the base areas are different. What must happen if you want the cylinders to have bases with different areas?
See solution.
Let's consider two right cylinders C_1 and C_2. Below, we write the surface area of each cylinder.
| Surface area of C_1 | Surface area of C_2 |
|---|---|
| S_1 = π r_1^2 + 2π r_1h_1 | S_2 = π r_2^2 + 2π r_2h_2 |
We are told that the lateral areas are equal, and so, if we want the cylinders to have different surface areas, the radius of the bases must be different. That is, r_1≠r_2.
r_1 ≠r_2 ⇒ h_1≠h_2
Let's find the lateral area of each cylinder, starting with C_1.
Next, let's find the lateral area of C_2.
As we can see, both cylinders have the same lateral area.
Let's finding the surface area C_1.
r_1= 3, L_(C_1)= 24Ï€
Calculate power
Add terms
Finally, let's find the surface area of C_2.
r_2= 4, L_(C_2)= 24Ï€
Calculate power
Add terms
As we wanted, both cylinders have different surface areas.
Below, we show the two cylinders with the dimensions used before.
Keep in mind that this is just an example, so your answer may vary.