McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
6. Surface Areas and Volumes of Spheres
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Exercise 3 Page 852

The surface area of a sphere is four times the product of π and the square of the radius.

452.4yd^2

Practice makes perfect

We will find the surface area of a sphere, and we are given the area of the great circle. The surface area of a sphere is four times the product of π and the square of the radius. S=4π r^2 Recall that the area of the great circle is the product of π and the square of the radius. A=π r^2 We are given that the area of the great circle is 36π yd^2. Let's substitute the given area for A and find the radius of the sphere.

A=Ï€ r^2
36Ï€=Ï€ r^2
36=r^2
6=r
r=6

Let's now substitute 6 for r in the formula for the surface area and simplify the right-hand side.

S=4Ï€ r^2
S=4Ï€ ( 6)^2
â–¼
Simplify right-hand side
S=4Ï€ (36)
S=4(36)Ï€
S=144Ï€
S=452.38...
S≈ 452.4

The surface area of the given sphere to the nearest tenth is 452.4yd^2.