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McGraw Hill Integrated II, 2012

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McGraw Hill Integrated II, 2012 View details

3. Arcs and Chords

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Exercise 40 Page 740

Consider the Perpendicular Chord Bisector Theorem.

D

Practice makes perfect

In the given diagram, we can extend WF so that it becomes a radius. The top part of the diagram is not important for solving the exercise.

Let's recall the Perpendicular Chord Bisector Theorem.

Perpendicular Chord Bisector Theorem
If a diameter or radius of a circle is perpendicular to a chord, then it bisects the chord and its arc.

Since the chord ED and the radius are perpendicular, we know that the radius bisects the chord. Chord length/Bisected → 30/2= 15 We found that the length of DF is 15, which corresponds to the option D.

Subchapter links

Exercises p.736-740