McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
3. Arcs and Chords
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Exercise 19 Page 737

If the chord and the diameter are perpendicular, then the diameter bisects the chord.

6.71

Practice makes perfect

We want to find the length of HP.

Since the chord and the diameter are perpendicular, we know that the diameter bisects the chord. This fact will help us find lengths later in the exercise. Since the diameter is 18, the radius must be 9. if we draw the radius HL we can create the right triangle △ LPH. Since the chord it bisected, we can determine the length of one of the triangle's legs. Chord length/Bisected → 12/2=6 To determine HP, we will substitute the known leg and hypotenuse into the Pythagorean Theorem.
a^2+b^2=c^2
HP^2+6^2=9^2
Solve for x
HP^2+36=81
HP^2=45
HP=± sqrt(45)

HP > 0

HP=sqrt(45)
HP=6.708...
HP≈ 6.71