McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Mid-Chapter Quiz
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Exercise 8 Page 661

Recall the Pythagorean Theorem.

AC≈180.3 ft

Let's begin with recalling the Pythagorean Theorem. In a right triangle, the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse.

a^2+ b^2= c^2 Now, let's look at the given picture which presents the small park in the corner of two perpendicular streets. We will name the point of intersection of these streets D.

Since △ ADC is a right triangle, we can use the Pythagorean Theorem to evaluate the length of AC. AC^2=AD^2+DC^2 Let's substitute the given side lengths and solve for AC. Notice that, since AC represents a length, we will consider only the positive case when taking a square root of AC^2.
AC^2=AD^2+DC^2
AC^2= 100^2+ 150^2
Solve for AC
AC^2=10000+22500
AC^2=32500
sqrt(AC^2)=sqrt(32500)
AC=sqrt(32500)
AC=180.2775...
AC≈180.3
The length of path AC is approximately 180.3 feet.