McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Using the Distributive Property
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Exercise 54 Page 41

Start with the product of two binomials (with four different variables), expand it, and simplify it. The final result will be the required four-term polynomial.

Example polynomial: 12px + 8py - 3qx - 2qy
Factored polynomial: (4p - q)(3x + 2y)

Practice makes perfect

Let's consider the following four-term polynomial. 12px + 8py - 3qx - 2qy As we can see, the first two terms have p in common and the last two terms have q in common. We should group them together. (12px + 8py) + (-3qx + 2qy) By writing 12 as 4* 3 and 8 as 4* 2, we can rewrite our polynomial above as follows. ( 4* 3 px + 4* 2 py) + ( -3 qx - 2 qy) Next, we can factor out 4p from the first two terms and - q from the last two terms. 4p( 3x + 2y) - q( 3x + 2y) Notice that ( 3x+2y) is common in both groups and we can factor it out. ( 4p - q)( 3x + 2y) As we can see, we have factored the initial polynomial by grouping. Keep in mind that the polynomial used here is just a sample and your answer may vary.

Extra

How to Find the Polynomial?
One way of finding the required polynomial is to start with the product of two binomials with four different variables. (4p - q)(3x + 2y) Second, we expand the product above and simplify it.

(4p - q)(3x + 2y)
4p(3x) + 4p(2y) - q(3x) - q(2y)
12px+8py-3qx-2qy

The resulting expression will be the required four-term polynomial.