We want to find the of the terms in the given expression. To do so, we will consider and separately.
27 cd^2- 18 c^2d^2+ 3 cd
Let's start by finding the GCF of 27, 18 and 3.
Factors of27:& 1, 3,9and27
Factors of18:& 1,2, 3,6,9and18
Factors of3:& 1 and 3
We found that the GCF of the coefficients is 3. To find the GCF of the variables, we need to identify the variables repeated in both terms, and write them with their minimum .
\begin{aligned}
\textbf{Factors of }\bm{1^\text{st}}\textbf{ Variable:}&\ c,d,{\color{#FF0000}{cd}},d^2,cd^2\\
\textbf{Factors of }\bm{2^\text{nd}}\textbf{ Variable:}&\ c,d,{\color{#FF0000}{cd}}, c^2,d^2\\
&\ cd^2,c^2d,c^2d^2\\
\textbf{Factors of }\bm{3^\text{rd}}\textbf{ Variable:}&\ c,d,{\color{#FF0000}{cd}}
\end{aligned}
We see that there is one repeated variable factor, cd.
Thus, the GCF of the expression is 3* cd= 3cd. Now we can write the given expression in terms of the GCF.
27cd^2-18c^2d^2+3cd ⇕ 3cd* 9d- 3cd* 6cd+ 3cd* 1
Finally, we will factor out the GCF.
3cd* 9d- 3cd* 6cd+ 3cd* 1 ⇕ 3cd(9d-6cd+1)
To check our answer, we can apply the and compare the result with the given expression.
3cd(9d-6cd+1)
3cd(9d)-3cd(6cd)+3cd(1)
27cd^2-18c^2d^2+3cd
After applying the Distributive Property, the result is the same as the given expression. Therefore, we can be sure our solution is correct!