body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Dashboard

MH

McGraw Hill Integrated II, 2012 View details

6. Solving x^2+bx+c=0

Continue to next subchapter

Exercise 41 Page 50

Factor the given expression.

Charles is correct.
Explanation: See solution.

Practice makes perfect

Let's try to factor the given expression by ourselves.

x^2+6x-16

WriteDiff

Write as a difference

x^2+8x-2x-16

▼

Factor out x & 8

FactorOut

Factor out x

x(x+8)-2x-16

FactorOut

Factor out - 2

x(x+8)-2(x+8)

FactorOut

Factor out (x+8)

(x-2)(x+8)

The factored form of the expression is (x-2)(x+8). x^2+6x-16=(x-2)(x+8) We see that Charles finds it correctly. However, Jerome incorrectly finds (x+2)(x-8). Correct: & x^2+6x-16= (x-2)(x+8) ✓ [0.5em] Incorrect: & x^2+6x-16= (x+2)(x-8) *