6. Solving x^2+bx+c=0
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Use the Distributive Property.
Use the table you completed in Part A.
Use the table you completed in Part A.
Consider the answers in Part B and C.
Table:
| Product of Two Binomials | ax^2+mx+px+c | ax^2+bx+c | m* p | a* c |
|---|---|---|---|---|
| (2x+3)(x+4) | 2x^2+8x+3x+12 | 2x^2+11x+12 | 24 | 24 |
| (x+1)(3x+5) | 3x^2+5x+3x+5 | 3x^2+8x+5 | 15 | 15 |
| (2x-1)(4x+1) | 8x^2+2x-4x-1 | 8x^2-2x-1 | - 8 | - 8 |
| (3x+5)(4x-2) | 12x^2-6x+20x-10 | 12x^2+14x-10 | - 120 | - 120 |
See solution.
See solution.
See solution.
We need to use the Distributive Property to complete the table.
| Product of Two Binomials | ax^2+mx+px+c | ax^2+bx+c | m* p | a* c |
|---|---|---|---|---|
| (2x+3)(x+4) | 2x^2+8x+3x+12 | 2x^2+11x+12 | 24 | 24 |
| (x+1)(3x+5) | 3x^2+5x+3x+5 | 3x^2+8x+5 | 15 | 15 |
| (2x-1)(4x+1) | 8x^2+2x-4x-1 | 8x^2-2x-1 | - 8 | - 8 |
| (3x+5)(4x-2) | 12x^2-6x+20x-10 | 12x^2+14x-10 | - 120 | - 120 |
From the table in Part A, we see that the product of m and p is equal to the product of a and c.
The second and third column in the table shows us that the sum of m and p is equal to b.
To factor trinomials in the form ax^2+bx+c, we first need to find two numbers, m and p, with a product of a* c and a sum of b.