McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
6. Solving x^2+bx+c=0
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Exercise 37 Page 50

Practice makes perfect
a

Let w be the variable that represents the width of the pool. Since the length of a rectangular swimming pool is 20 feet longer than its width, w+20 represents the length as shown below.

Given that the area of the pool is 525 square feet, we can write the following using the formula for the area of a rectangle. A= w * l ⇓ 525= w * (w+20)

b

We will solve the equation by factoring and using the Zero Product Property.

525= w * (w+20)
525=w^2+20w
0=w^2+20w-525
â–¼
Factor
w^2-15w+35w-525=0
w(w-15)+35w-525=0
w(w-15)+35(w-15)=0
(w+35)(w-15)=0

To solve this equation, we will apply the Zero Product Property.

(w+35)(w-15)=0
lcw+35=0 & (I) w-15=0 & (II)
lw=- 35 w-15=0
lw=- 35 w=15

The solutions of the equation are - 35 and 15.

c

Only the positive solution makes sense because length cannot be negative. Therefore, the width is 15 feet and the length is 35 feet.

Length:& w+20= 35 ft Width:& w =15 ft