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Start by identifying the values of a, b, and c.
(m-5)(m-10)
To factor the quadratic expression, we will start by identifying the values of a, b, and c.
m^2-15m+50
⇕
1m^2+( - 15)m+ 50
For our expression, we have that a= 1, b= - 15, and c= 50.
To factor a quadratic expression with leading coefficient a= 1, we need to find two factors of c= 50 whose sum is b= - 15. Since 50 is a positive number, we will only consider factors with the same sign — both positive or both negative — so that their product is positive.
| Factor Pair | Product | Sum |
|---|---|---|
| 1 and 50 | ^(1* 50) 50 | 1+50 51 |
| - 1 and - 50 | ^(- 1* (- 50)) 50 | ^(- 1+(- 50)) - 51 |
| 2 and 25 | ^(2* 25) 50 | ^(2+25) 27 |
| - 2 and - 25 | ^(- 2* (- 25)) 50 | ^(- 2+(- 25)) - 27 |
| 5 and 10 | ^(5* 10) 50 | ^(5+10) 15 |
| - 5 and - 10 | ^(- 5* (- 10)) 50 | ^(- 5+ (- 10)) - 15 |
The integers whose product is 50 and whose sum is - 15 are - 5 and -10. m^2-15m+50 ⇔ (m-5)(m-10) Let's use a graphing calculator to confirm our answer. To do so, we will graph the related functions in the same coordinate plane. Note that in the calculator we will use the variable x instead of m.
We see that only one graph appears. This means that both graphs coincide. Therefore, the expression has been factored correctly.