Start by identifying the values of a, b, and c.
Be sure that all of the terms are on the same side and in the correct order for the standard form of a quadratic function.
5/2, 4
To solve the given equation by factoring, we will start by identifying the values of a, b, and c.
2x^2-13x+20=0
⇕
2x^2+( - 13)x+ 20=0
We have a quadratic equation with a= 2, b= - 13, and c= 20. To factor the left-hand side, we need to find a factor pair of 2 * ( 20)=40 whose sum is - 13.
Since 40 is a positive number, we will only consider factors with the same sign — both positive or both negative — so that their product is positive.
Factor Pair
Product of Factors
Sum of Factors
1 and 40
^(1* 40) 40
1+40 41
- 1 and - 40
^(- 1* (- 40)) 40
- 1+(- 40) - 41
2 and 20
^(2* 20) 40
2+20 22
- 2 and - 20
^(- 2* (- 20)) 40
- 2+(- 20) - 22
4 and 10
^(4* 10) 40
4+10 14
- 4 and - 10
^(- 4* (- 10)) 40
- 4+(- 10) - 14
5 and 8
^(5* 8) 40
5+8 13
- 5 and - 8
^(- 5* (- 8)) 40
- 5+(- 8) - 13
The integers whose product is 40 and whose sum is - 13 are - 5 and - 8. With this information, we can rewrite the linear factor on the left-hand side of the equation, and factor by grouping.
We found that the solutions to the given equation are x=4 and x= 52. To check our answer, we will graph the given function y=2x^2-13x+20 using a calculator.
We can see that the x-intercepts are 52 and 4. Therefore, the solutions are correct.
