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(x+1)(x+6)
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term.
x^2+7x+6
In this case, we have 6. This is a positive number, so for the product of the constant terms in the factors to be positive, these constants must have the same sign (both positive or both negative).
| Factor Constants | Product of Constants |
|---|---|
| 1 and 6 | 6 |
| -1 and -6 | 6 |
| 2 and 3 | 6 |
| -2 and -3 | 6 |
Next, let's consider the coefficient of the linear term. x^2+7x+6 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, 7.
| Factors | Sum of Factors |
|---|---|
| 1 and 6 | 7 |
| -1 and -6 | -7 |
| 2 and 3 | 5 |
| -2 and -3 | -5 |
We found the factors whose product is 6 and whose sum is 7. x^2+ 7x+ 6 ⇔ (x+1)(x+6)