McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
9. Perfect Squares
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Exercise 59 Page 70

Write the difference of squares pattern. Then, rewrite the binomial that has terms with opposite signs as a new difference of squares with new variables — one variable and one constant. Finally, rewrite the original binomial in terms of the new variables and solve it.

Example binomial: x^4-16
Solutions: x=-2 and x=2

Practice makes perfect
Let's begin by writing the difference of squares pattern. a^2 - b^2 = ( a+ b)( a- b) We are required to find a binomial where we need to apply this pattern twice to factor it. By looking at the expression above, it implies that the factor ( a- b) also has to be a difference of two squares. For example, it can be equal to x^2-2^2. a- b = x^2-2^2 From the above equation we can consider a=x^2 and b=2^2. With these two new variables, the difference of squares looks as follows. a^2- b^2 &= (x^2)^2-(2^2)^2 &= x^4-16 Next, we set our binomial equal to zero. x^4-16 = 0 Finally, let's solve this equation.
x^4-16 = 0
(x^2)^2-16 = 0
â–Ľ
Solve for x
(x^2)^2-4^2 = 0
(x^2+4)(x^2-4) = 0
(x^2+4)(x^2-2^2) = 0
(x^2+4)(x+2)(x-2) = 0
lcx^2+4=0 & (I) x+2=0 & (II) x-2=0 & (III)
lx^2+4=0 x=-2 x-2=0
lx^2+4=0 x=-2 x=2
Equation (I) has no real solutions. This means that the solutions to our binomial equation are x=-2 and x=2. Keep in mind that this is just an example binomial and your answer may vary.

Extra

Extra
Let's see why x^2+4=0 does not have real solutions.
x^2+4=0
x^2 = -4
x = ± sqrt(-4)
Since sqrt(-4) is not a real number, the original equation has no real solutions.