McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
9. Perfect Squares
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Exercise 52 Page 70

Create a polynomial using the given dimensions. Then, solve for height.

12 ft long by 4 ft high by 2 ft wide

Practice makes perfect
We can begin by creating a polynomial for the volume of the prism in terms of h, as the product of the given dimensions. h ( h+8)(h-2) Next, we simplify the expression.
h ( h+8)(h-2)
h (h( h+8)-2( h+8) )
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Distribute h and -2
h (h^2+8h-2( h+8) )
h (h^2+8h-2h-16 )
h (h^2+6h-16 )
h^3+6h^2-16h
Next, we create an equation with the expression equal to the volume, 96, and solve for the width.
h^3+6h^2-16h=96
h^3+6h^2-16h-96=0
We can split the equation into two parts and factor out the common factors. ( h^3+6h^2)+(-16h- 96) ⇕ h^2(h+6)-16(h+6) ⇕ (h^2-16)(h+6) Notice that (h^2-16) is a difference of squares. This means that we can factor it as follows. (h^2-16)(h+6) ⇕ (h+4)(h-4)(h+6) Then, we can set each factor equal to 0 and solve for h. rcl h+4=0 & ⇒ & h= -4 h-4=0 & ⇒ & h=4 h+6=0 & ⇒ & h=-6 We can identify that the only positive solution is h=4. Therefore, the height is 4ft and we can use the given expressions for length and depth to find the other dimensions.
Expression Substitution Dimension
Height -- -- h=4
Length l= h+8 l= 4+8 l=12
Width w= h-2 w= 4-2 w=2