body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

9. Perfect Squares

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Exercise 45 Page 69

Use square roots to solve for d.

20 ft

Practice makes perfect

We can begin by substituting the given area, 100, for A. Next, we can solve for d.

A=0.25d^2

A= 100

100=0.25d^2

.LHS /0.25.=.RHS /0.25.

100/0.25=d^2

Divide by 0.25

400=d^2

sqrt(LHS)=sqrt(RHS)

sqrt(400)=d

Calculate root

20=d

At 20 ft, the projected picture will have an area of 100 ft^2.

Subchapter links

Exercises p.68-71