To solve this equation take the square root of each side.
8±sqrt(6)
Practice makes perfect
Notice that on the left hand side of the given equation we have a perfect square trinomial. To solve a quadratic equation in the form x^2=n, we will take the square root of each side. For any number n≥ 0, if x^2=n, then x=±sqrt(n). Keeping this in mind let's consider the given equation.
We found that the solutions to the given equation are x=8-sqrt(6) and x=8+sqrt(6). To check our answer, let's find the related functions. We will write the first one using the two roots we found.
(x-( 8 - sqrt(6)))(z-( 8 + sqrt(6))) ⇕ (x-8+sqrt(6))(x-8-sqrt(6))
To find the second one we will use the given equation.