McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
9. Perfect Squares
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Exercise 36 Page 69

Start by identifying the values of a, b, and c of the related quadratic expression.

- 5/7

Practice makes perfect
To solve the given equation by factoring, we will start by identifying the values of a, b, and c. a^2 +10/7a +25/49=0 ⇔ 1a^2 + 10/7a + 25/49=0 Notice that this equation follows a special pattern. It can be factored as a perfect square trinomial.
a^2+10/7a+25/49=0
(a+5/7)^2=0
Now we are ready to use the Zero Product Property.
(a+5/7)^2=0
a+5/7=0
a=- 5/7
We found that the solution to the given equation is x=- 57. To check our answer, we will graph the related functions y=x^2+ 107x+ 2549 and y=(x+ 57)^2 in the same coordinate plane using a graphing calculator. Note that in the calculator we will use the variable x instead of a.

We see that only one graph appears. This means that both graphs coincide. Therefore, - 57 is the correct solution. âś“