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Is there a greatest common factor? What other factoring technique could be used according to the number of terms?
2(b^2+6b-12)
Split into factors
Factor out 2
Since 12 is not a perfect square, we cannot write the given expression as perfect square trinomial. Let's try the other method. First, we will identify the values a, b, and c. b^2+6b-12 ⇔ 1b^2+ 6b +( -12) For our expression, we have that a= 1, b= 6, and c= - 12. We want to check if we can find a pair of integers with a product of a * c and a sum of b. In this case the product is 1( -12)=-12 and the sum is 6. Let's do it!
| Factor Pair | Product | Sum |
|---|---|---|
| -1 and 12 | -1* 12 - 12 | -1+12 11 |
| 1 and -12 | 1* (-12) -12 | 1 +(-12) -11 |
| -2 and 6 | -2* 6 -12 | -2+6 4 |
| 2 and -6 | 2* (-6) -12 | 2+(-6) -4 |
| -3 and 4 | -3* 4 - 12 | -3+4 1 |
| 3 and -4 | 3* (-4) - 12 | 3+(-4) -1 |
We cannot find a pair of integers whose product is -12 and whose sum is 6. Therefore, we cannot general method for factoring trinomials. The given polynomial cannot be factored, so it is prime.