Exercise 11 Page 68

We can begin by identifying that h_0 is the initial height from which we are dropping the brush. When the brush hits the ground is h. Therefore, we can substitute 0 for h and 6 for h_0. h=-16t^2+ h_0 ⇒ 0=-16t^2+ 6 Next, we can solve for t.

Mathematically our solution can be positive or negative. However, a negative solution does not make sense in this scenario. Our solution must then be t=0.6.