McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
8. Differences of Squares
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Exercise 13 Page 60

After the substitution, rewrite the equation so that there is a difference of two squares on the left-hand side.

36 mph

Practice makes perfect
To find the speed of the car, we will use the given formula. 1/24 s^2= d Here, s is the vehicle's speed in miles per hour and d is the length of the skid marks in feet. We need to substitute 54 for d into this formula.
1/24s^2=d
1/24s^2= 54
s^2=1296
Notice that 1296 is the square of 36. Let's rewrite it so all terms are on the left-hand side and then factor it.
s^2=1296
s^2=36^2
s^2-36^2=0
(s-36)(s+36)=0
To solve this equation, we will apply the Zero Product Property.
(s-36)(s+36)=0
lcs-36=0 & (I) s+36=0 & (II)
ls=36 s+36=0
ls_1=36 s_2=- 36
Since speed cannot be negative, we ignore the negative solution. The speed of the car is 36 mph.