McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
6. The Law of Sines and Law of Cosines
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Exercise 35 Page 594

Use The Law of Sines and relate the sine of each angle to the length of the opposite side.

m ∠ G = 75
GH≈ 19.9
GJ≈ 11.8

Practice makes perfect

Let's begin by color coding the opposite angles, sides, and the vertices in the given triangle. It will help us to use the Law of Sines later.

Let's first find the measure of the third interior angle which is m∠ G, and then the measures of the missing side lengths one at a time.

Finding m ∠ G

To find m ∠ G we can use the Triangle Angle Sum Theorem. This tells us that the measures of the angles in a triangle add up to 180.

m∠ G+ 34 + 71 = 180 ⇔ m ∠ G = 75

Finding GH

Note that we know the m ∠ G and the length of the side which is opposite to this angle. We want to find the length of the side j that is opposite to the ∠ J. Therefore, it is time to use the Law of Sines! sin G/g =sin J/j Let's substitute g= 20.3, m ∠ G= 75, and m ∠ J= 71 to isolate j.

sin G/g =sin J/j
sin 75/20.3 = sin 71/j
Solve for j
j sin 75 = 20.3sin 71
j = 20.3 sin 71/sin 75
j = 19.871119...
j ≈ 19.9
We found that the length of the side GH is about 19.9 units.

Finding GJ

Finally, to find GJ we will use the Law of Sines one more time. sin G/g =sin H/h Let's substitute g= 20.3, m ∠ G= 75, and m ∠ H= 34 to isolate h.
sin G/g =sin H/h
sin 75/20.3 = sin 34/h
Solve for h
h sin 75 = 20.3 sin 34
h = 20.3 sin 34/sin 75
h = 11.752057 ...
h ≈ 11.8
We found that the length of the side GJ is about 11.8 units.

Completing the Triangle

With all of the angle measures and side lengths, we can complete our diagram.