Sign In
Follow the instructions you are given in the book.
Use a protractor to measure appropriate angles, and record the results in a table.
What can you say about the angles of triangles looking at the table you made in the previous part?
See solution.
See solution.
If an altitude in a right triangle is drawn from a right angle, then it divides this triangle into two triangles that are similar to the original one.
First, we are asked to draw â–³ ABC with the right angle at vertex B and an altitude BD.
Next, we will draw two more right triangles MNP and WXY with the right angles at vertices N and X respectively. In each triangle we will draw its altitude from its right angle.
In this part we are asked to measure and record the indicated angles. To do this, we will use a protractor. Let's start with â–³ ABC.
Now we can complete the table using the angle measures we found.
| Angle Measures | ||||||
|---|---|---|---|---|---|---|
| â–³ ABC | â–³ ABC | â–³ BDC | â–³ ADB | |||
| ABC | 90^(∘) | BDC | 90^(∘) | ADB | 90^(∘) | |
| A | 45^(∘) | CBD | 45^(∘) | BAD | 45^(∘) | |
| C | 45^(∘) | DCB | 45^(∘) | DBA | 45^(∘) | |
| â–³ MNP | â–³ MNP | â–³ NQP | â–³ MQN | |||
| MNP | 90^(∘) | NQP | 90^(∘) | MQN | 90^(∘) | |
| M | 52^(∘) | PNQ | 52^(∘) | NMQ | 52^(∘) | |
| P | 38^(∘) | QPN | 38^(∘) | QNM | 38^(∘) | |
| â–³ WXY | â–³ WXY | â–³ WZX | â–³ XZY | |||
| WXY | 90^(∘) | WZX | 90^(∘) | XZY | 90^(∘) | |
| W | 60^(∘) | XWZ | 60^(∘) | YXZ | 60^(∘) | |
| Y | 30^(∘) | ZXW | 30^(∘) | ZYX | 30^(∘) | |
Looking at the table we made in Part B, we can see that all three triangles in each row are similar by the Angle-Angle Similarity Theorem. Therefore, we can assume that if an altitude in a right triangle is drawn from a right angle, then it divides this triangle into two triangles that are similar to the original one.