Study Guide and Review
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Begin by finding the slopes of the sides.
Type of Quadrilateral: Rhombus
Explanation: See solution.
Let's plot the given points on a coordinate plane and graph the quadrilateral.
| Quadrilateral | Definition |
|---|---|
| Rhombus | Parallelogram with four congruent sides. |
| Rectangle | Parallelogram with four right angles. |
| Square | Parallelogram with four congruent sides and four right angles. |
Now, let's find the slopes of the sides using the Slope Formula.
| Slope Formula: y_2-y_1/x_2-x_1 | |||
|---|---|---|---|
| Side | Endpoints | Substitute | Simplify |
| QR | Q( - 2,4) and R( 5,6) | 6- 4/5-( - 2) | 2/7 |
| RS | R( 5,6) and S( 12,4) | 4- 6/12- 5 | - 2/7 |
| ST | S( 12,4) and T( 5,2) | 2- 4/5- 12 | 2/7 |
| TQ | T( 5,2) and Q( - 2, 4) | 4- 2/- 2- 5 | - 2/7 |
We can tell that the consecutive side are not perpendicular, as their slopes are not opposite reciprocals. 2/7 ( - 2/7 ) ≠ -1 Therefore, our parallelogram is neither a rectangle nor a square. To check if it is a rhombus, we can find the lengths of its sides using the Distance Formula.
| Distance Formula: sqrt((x_2-x_1)^2+(y_2-y_1)^2) | |||
|---|---|---|---|
| Side | Endpoints | Substitute | Simplify |
| QR | Q( - 2,4) and R( 5,6) | sqrt(( 5-( - 2))^2+( 6- 4)^2) | sqrt(53) |
| RS | R( 5,6) and S( 12,4) | sqrt(( 12- 5)^2+( 4- 6)^2) | sqrt(53) |
| ST | S( 12,4) and T( 5,2) | sqrt(( 5- 12)^2+( 2- 4)^2) | sqrt(53) |
| TQ | T( 5,2) and Q( - 2, 4) | sqrt(( - 2- 5)^2 + ( 4- 2)^2) | sqrt(53) |
Our parallelogram has four congruent sides. Therefore, it is a rhombus.