McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
1. Bisectors of Triangles
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Exercise 32 Page 331

Let's start with examining the given diagram. We will name some of the points for the purposes of the solution.

We can see that angles and are congruent and have the same measure. Thus, is the bisector of Let's now recall what the Angle Bisector Theorem states.
Point lies on the angle bisector According to this theorem, it must be equidistant from the sides of the angle and From the diagram, it might seem like and are the distances from to and Then we would conclude that they are the same and equals However, is it really so?

Let's remember that the distance from a point to a line/arrow is the length of the line segment, which joins the point to the line and is perpendicular to the line, as illustrated below.

We do not know if the segments and are perpendicular to and or not (and from what we see on the above diagram, it's possible that they are not). Thus, these may not be the distances from to the sides of the angle, and we cannot use the statement of the theorem. Therefore, there is not enough information to find