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McGraw Hill Glencoe Geometry, 2012

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McGraw Hill Glencoe Geometry, 2012 View details

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Exercise 26 Page P21

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

$b = 8$

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. In this case, we need to start by using the Distributive Property to simplify the left-hand side of the equation.

3 (20 - b) = 36

Distribute $3$

60 - 3 b = 36

Now we can continue to solve using the Properties of Equality.

60 - 3 b = 36

$LHS - 60 = RHS - 60$

- 3 b = - 24

$LHS / (- 3) = RHS / (- 3)$

b = 8

The solution to the equation is

b = 8 .

Subchapter links

Exercises p.21-P21