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Start by stating the excluded values. These are the values for which the denominator is 0 in any fraction of the related rational equation.
x<-5 or 4
To solve the given rational inequality, we will follow four steps.
Let's deal with these steps one at a time.
Consider the given inequality.
x/5+2/3<3/x-4
Let's find the values for which any of the denominators is 0.
x-4=0
⇕
x=4
We obtain the related equation by replacing the inequality sign with an equals sign. c|c Inequality & Equation [0.8em] x/5+2/3 < 3/x-4 & x/5+2/3 = 3/x-4 Let's solve the equation. First, we will get rid of all of the denominators by multiplying the equation by the least common denominator (LCD). The LCD of the given equation in 3(5)(x-4).
LHS * 3 (5) (x-4)=RHS* 3 (5) (x-4)
Distribute 3(5)(x-4)
Cancel out common factors
Simplify quotient and product
Now that we have an equation without any denominators, we can simplify it as much as possible.
Distribute 3x & 10
Add and subtract terms
LHS-45=RHS-45
We obtained a quadratic equation. Let's identify the values of a, b, and c. 3x^2-2x-85=0 ⇕ 3x^2+( - 2)x+( -85)=0 We have that a= 3, b= - 2, and c= -85. We will solve this equation by substituting these values into the Quadratic Formula.
Substitute values
- (- a)=a
Calculate power and product
Subtract terms
Calculate root
We will find the solutions by dividing our answer in two using the positive and negative sign.
| x=2± 32/6 | |
|---|---|
| x=2- 32/6 | x=2+ 32/6 |
| x=-30/6 | x=34/6 |
| x=-5 | x=17/3 |
The solutions to the equation are x=-5 and x= 173.
We will divide the number line considering the excluded value x= 4 and the solutions to the related equation x=-5 and x= 173.
We will now test a value from each interval. Let's start with the interval x<- 5. We will test the point x=- 10. If substituting this point into the original inequality produces a true statement, then the numbers in this interval are solutions. If not, these numbers are not solutions.
x= - 10
Subtract terms
Put minus sign in front of fraction
a/b=a * 3/b * 3
a/b=a * 5/b * 5
Add fractions
a/b=.a /5./.b /5.
Multiply by (- 1) and flip inequality sign
LHS* 3 > RHS * 3
a/c* b = a* b/c
LHS* 14 > RHS * 14
Since we obtained a true statement, we can conclude that the numbers less than - 5 are solutions to the inequality. Using the same process, we can determine whether the numbers that belong to the other intervals are solutions.
| Interval | Test Value | Statement |
|---|---|---|
| x< - 5 | x=- 10 | 56 > 9 ✓ |
| - 5< x < 4 | x=0 | 8<- 9 * |
| 4 | x=5 | 4 <9 ✓ |
| x>17/3 | x=10 | 16 <3 * |
We found that the solutions to the given inequality are all the numbers less than - 5, or between 4 and 173.
Solution
x<-5 or 4