McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
1. Graphing Exponential Functions
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Exercise 27 Page 456

Practice makes perfect
a
The function P(x)=2.28(0.9)^x can be classified as an exponential decay function because P(x) decreases by the same factor, 0.9, as x increases. For an exponential decay function, the base of the exponential expression is called the decay factor, which is 0.9 for P(x).

P(x)=2.28(0.9)^x Now that we have classified the function, we can graph the function showing the decrease in the number of pay phones in millions x years since 1999. To do so, we will first make a table of values.

x 2.28(0.9^x) P(x)=2.28(0.9^x)
1 2.28(0.9)^1 ≈ 2.05
2 2.28(0.9)^2 ≈ 1.85
3 2.28(0.9)^3 ≈ 1.66
4 2.28(0.9)^4 ≈ 1.50
5 2.28(0.9)^5 ≈ 1.35

Note that P(x) gives the number of payphones in millions. Let's now plot and connect the points ( 1, 2.05), ( 2, 1.85), ( 3, 1.66), ( 4, 1.50), and ( 5, 1.35) with a smooth curve.

b To find the y-intercept, we need to substitute 0 for x in the function. Let's do it!
P(x)=2.28(0.9^x)
P( 0)=2.28(0.9)^0
Simplify right-hand side
P(0)=2.28(1)
P(0)=2.28
The function intercepts the y-axis at 2.28, which tells us that the number of pay phones in 1999 is equal to 2.28 million. As x increases, y-values approach the x-axis and never equal to zero. Therefore, the asymptote is the x-axis. As a result, this model foresees that the number of pay phones will never be zero.