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Substitute 1.25* 10^(- 11) for H into the given formula and check if the result is smaller than 9.5 pH.
Compute parts per million (ppm) and check if the result is smaller than 0.025, which is the safe standard.
Substitute 9.5 for pH into the given formula and solve it for H.
The environmental engineer should be worried about too high an arsenic content.
The tested well is not safe.
The hydrogen ion concentration around 3.16* 10^(- 10) ppm meets the troublesome pH level of 9.5.
Let's analyze the given formula.
Since 10.9 is greater than 9.5, the environmental engineer should be worried about too high an arsenic content.
The safe standard for arsenic is 0.025 parts per million (ppm). The environmental engineer finds 1 milligram of arsenic in a 3 liter sample. Since 1 liter of water is around 1 kilogram, let's find out the ratio of arsenic in the tested water.
Let's analyze the given formula.
pH=-log H
H is the hydrogen ion concentration. We are asked to find the hydrogen ion concentration that meets the troublesome pH level of 9.5. Let's substitute 9.5 for pH into the given formula and solve it for H.
To solve the equation for H, we will use the definition of a logarithm. Notice also that log x is equal to log_(10)x for all x. y=log_b x ⇔ x= b^y This definition tells us how to rewrite the logarithm equivalent of y as an exponential equation. The argument x is equal to b raised to the power of y. Let's do it! - 9.5=log_(10) H ⇔ H= 10^(- 9.5) Finally, using a calculator, we get that H=10^(- 9.5)≈ 3.16* 10^(- 10) ppm. Therefore, the hydrogen ion concentration around 3.16* 10^(- 10) ppm meets the troublesome pH level of 9.5.