McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
6. Common Logarithms
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Exercise 39 Page 496

Practice makes perfect
a

Let's analyze the given equation.

n=35[log_4(t+2)] The variable n is the number of pet owners in thousands after t years after 2000. We are asked to find the number of pet owners in 2010. Therefore, we substitute 10 for t into the given equation.

n=35[log_4(t+2)]
n=35[log_4( 10+2)]
n=35[log_4(12)]

Now, we will use the Change of Base Formula. y=log_a b ⇒ y=log_()darkorangec b/log_()darkorangec a This formula allows us to change the base of a logarithm. In our case, we will change the base to 10 to calculate the value more easily using a calculator. n=35[log_4(12)] ⇒ n=35*log_(10)12/log_(10)4 Finally, using a calculator, we can get that n≈ 62.737. Therefore, in 2010 there was around 62.737 thousands of pet owners, or simply just 62 737 pet owners.

b

Since we want to know the year in which there will be 80 thousands pet owners, we will substitute 80 for n into the given equation.

n=35[log_4(t+2)]
80=35[log_4(t+2)]
80/35=log_4(t+2)
2.29≈ log_4(t+2)

To solve the equation for E, we will use the definition of a logarithm. Notice also that log x is equal to log_(10)x for all x.

y=log_b x ⇔ x= b^y This definition tells us how to rewrite the logarithm equivalent of y as an exponential equation. The argument x is equal to b raised to the power of y. Let's do it! 2.29=log_4( t+2) ⇔ t+2= 4^(2.29) Next, we will solve it for t.

t+2=4^(2.29)
t=4^(2.29)-2
t≈ 22

Therefore, it will take about 22 years. It will occur in 2022.