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McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
Study Guide and Review
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Exercise 79 Page 442

Start by identifying the values of x for which the inequality is defined.

No solution.

Practice makes perfect

Before solving the radical inequality, recall that the radicand of a square root must be greater than or equal to 0. 5+ sqrt(2y-7)< 5 Let's start by identifying any values of x for which the inequality is defined.

2y-7 ≥ 0
AddIneq

LHS+7≥RHS+7

2y ≥ 7
DivIneq

.LHS /2.≥.RHS /2.

y ≥ 7/2

After we solve the given inequality, we can combine the above information to obtain the final solution set. Let's now solve the inequality.

5+ sqrt(2y-7) < 5
SubIneq

LHS-5

sqrt(2y-7) < 0
RaiseIneq

LHS^2

( sqrt(2y-7) ) ^2 < 0
PowSqrt

( sqrt(a) )^2 = a

2y-7 < 0
â–¼
Solve for y
AddIneq

LHS+7

2y < 7
DivIneq

.LHS /2.<.RHS /2.

y< 7/2

Now we can combine the two intervals.

The intersection of both solutions is an empty set, which means there is no solution for the given inequality.

Subchapter links expand_more
arrow_right Exercises p.438-442
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