McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
Study Guide and Review
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Exercise 40 Page 440

Start by drawing the boundary curve. Recall that the domain of radical functions only includes values for which the radicand is non-negative.

Practice makes perfect

To graph the given inequality, we will start by drawing its boundary curve. y=- sqrt(x-1)+2 To do so, we first need to find the domain. For radical functions, the domain only includes values for which the radicand is non-negative.

x-1 ≥ 0
x ≥ 1

Now we will make a table of values, using a variety of values for x greater than or equal to 1.

x - sqrt(x-1)+2 y
1 - sqrt(1 -1)+2 2
2 - sqrt(2 -1)+2 1
3 - sqrt(3 -1)+2 ≈ 0.586
4 - sqrt(4 -1)+2 ≈ 0.268
5 - sqrt(5 -1)+2 0
6 - sqrt(6 -1)+2 ≈ - 0.236

Let's plot the points and connect them with a smooth curve.

Finally, we can determine the region to shade using a test point. If the test point produces a true statement when substituted into the given inequality, we will shade the region that contains it. If it produces a false statement, we will shade the region which does not contain the test point. We will use the point (2,0).

y >- sqrt(x-1)+2
0? >- sqrt(2-1)+2
â–¼
Simplify right-hand side
0? >- sqrt(1)+2
0? >- 1+2
0>1 *

Since the point did not produce a true statement, we will shade the region that does not contain (2,0). Note that we are given a strict inequality, so the curve will be dashed.