body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Glencoe Algebra 2, 2012

MH

McGraw Hill Glencoe Algebra 2, 2012 View details

Standardized Test Practice

Exercise 9 Page 380

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

D

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side, using the Properties of Equality. In this case, we will use the Properties of Equality.

4x-5=2x+5-3x

LHS+5=RHS+5

4x=2x+5-3x+5

LHS+3x=RHS+3x

4x+3x= 2x+5+5

LHS-2x=RHS-2x

4x+3x-2x= 5+5

Add and subtract terms

5x=10

.LHS /5.=.RHS /5.

x=2

The solution to the equation is x=2. This corresponds to answer D.

Subchapter links

Exercises p.380-381