McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
Study Guide and Review
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Exercise 17 Page 207

Does either of the equations have an isolated variable in it?

(-2,-7)

Practice makes perfect

In this system of equations, at least one of the variables has a coefficient of 1. Therefore, we will approach its solution with the Substitution Method. When solving a system of equations using this method, there are three steps.

  1. Isolate a variable in one of the equations.
  2. Substitute the expression for that variable into the other equation and solve.
  3. Substitute this solution into one of the equations and solve for the value of the other variable.

Observing the given equations, it looks like it will be simplest to isolate x in the second equation.

5x-2y=4 & (I) -2y+x=12 & (II)
5x-2y=4 x=2y+12

Now that we've isolated x, we can solve the system by substitution.

5x-2y=4 x=2y+12
5( 2y+12)-2y=4 x=2y+12
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(I):Solve for y
10y+60-2y=4 x=2y+12
8y+60=4 x=2y+12
8y=-56 x=2y+12
y=-7 x=2y+12

Great! Now, to find the value of x, we need to substitute y=-7 into Equation (II).

y=-7 x=2y+12
y=-7 x=2( -7)+12
y=-7 x=-14+12
y=-7 x=-2

The solution, or point of intersection, to this system of equations is the point (-2,-7).