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Begin by writing an equation for the boundary lines. If below the boundary line is shaded the inequality symbol will be ≤. If above the boundary line is shaded, the inequality symbol will be ≥.
Example System:y ≤ -1/2x+4 y ≥ 2x-6 y ≥ -6x-6
For the given boundary lines, we can immediately determine their y-intercepts and with this we can find their slopes. Let's first indicate their y-intercepts!
Next, we will indicate another point on each line to find their slopes.
Substitute ( 0,4) & ( 4,2)
Subtract terms
a/b=.a /2./.b /2.
| Boundary Line | Points | m=y_2-y_1/x_2-x_1 | Slope | y-intercept | Equation |
|---|---|---|---|---|---|
| I: | ( 0, 4),( 4, 2) | m=2- 4/4- 0 | -1/2 | ( 0, 4) | y= -1/2x+ 4 |
| II: | ( 0, -6),( 4, 2) | m=2-( -6)/4- 0 | 2 | ( 0, -6) | y= 2x -6 |
| III: | ( 0, -6),( -2, 0) | m=0-( -6)/-2- 0 | -3 | ( 0, -6) | y= -6x -6 |
In our last step, we will decide the inequality symbols. Since the boundary lines are in slope-intercept form, we have a special way to decide the symbols. If below the boundary line is shaded the inequality symbol will be ≤. If above the boundary line is shaded, the inequality symbol will be ≥. ccc & &Boundary Line &Inequality [0.5em] &I: &y = -1/2x+4 &y ≤ -1/2x+4 &II: &y =2x-6 &y ≥ 2x-6 &III: & y = -6x-6 & y ≥ -6x-6 Finally, we have three inequalities to write a system. y ≤ -1/2x+4 y ≥ 2x-6 y ≥ -6x-6