8. Solving Systems of Equations Using Inverse Matrices
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Introduce variables for the amount of blue and red food coloring needed.
19ml blue and 6ml red
Let's introduce variables for the amount of blue and red food coloring Peggy needs to make purple.
| Description | Variable |
|---|---|
| Blue food coloring | bml |
| Red food coloring | rml |
Let's use these variables to write equations expressing the information given in the question.
| Description | Equation |
|---|---|
| Peggy needs 25ml food coloring. | b+r=25 |
| The amount of food coloring in bml 50 % concentration blue food coloring. | 0.50bml |
| The amount of food coloring in rml 25 % concentration red food coloring. | 0.25rml |
| The amount of food coloring in 25ml 44 % concentration mix. | 0.44* 25=11ml |
| The coloring in the mix comes from the blue and red concentration. | 0.50b+0.25r=11 |
1/-0.25 0.25& -1 -0.50& 1 * LHS = 1/-0.25 0.25& -1 -0.50& 1 * RHS
Multiply matrices
Multiply matrices
Now that the left-hand side is only the variable matrix, we can simplify the right-hand side to find the values of the variables.
Multiply matrices
Multiply
Add terms
Multiply matrix by 1/-0.25
This result means that Peggy needs b=19ml blue and r=6ml red food coloring concentration.