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McGraw Hill Glencoe Algebra 2, 2012

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McGraw Hill Glencoe Algebra 2, 2012 View details

3. Rate of Change and Slope

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Exercise 57 Page 82

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

x=7/3

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side, using the Properties of Equality. In this case, the variable term is already on the right-hand side of the equation, so we will start by subtracting 5 from both sides of the equation.

- 2=- 3x+5

LHS-5=RHS-5

- 2-5=- 3x+5-5

Subtract terms

- 7=- 3x

.LHS /(- 3).=.RHS /(- 3).

- 7/- 3=- 3x/- 3

▼

Simplify

Calculate quotient

- 7/- 3=x

- a/- b=a/b

7/3=x

Rearrange equation

x=7/3

The solution to the equation is x= 73.

Subchapter links

Check Your Understanding p.79

Practice and Problem Solving p.79-81

H.O.T. Problems p.81

Standardized Test Practice p.82

Spiral Review p.82

Skills Review p.82